If it's not what You are looking for type in the equation solver your own equation and let us solve it.
5x^2-9=15
We move all terms to the left:
5x^2-9-(15)=0
We add all the numbers together, and all the variables
5x^2-24=0
a = 5; b = 0; c = -24;
Δ = b2-4ac
Δ = 02-4·5·(-24)
Δ = 480
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{480}=\sqrt{16*30}=\sqrt{16}*\sqrt{30}=4\sqrt{30}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{30}}{2*5}=\frac{0-4\sqrt{30}}{10} =-\frac{4\sqrt{30}}{10} =-\frac{2\sqrt{30}}{5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{30}}{2*5}=\frac{0+4\sqrt{30}}{10} =\frac{4\sqrt{30}}{10} =\frac{2\sqrt{30}}{5} $
| 2f+10=18 | | -3-8=-2c | | 7x+2-5x+3=15 | | 140=-7(-4x+8) | | -6(x-7)-x=112 | | 5+8w=3w | | -.6n=9.6 | | 7k+3.9=27.7 | | x5+15=50 | | 9=1-d=-7 | | 5x-(14-x)=-20-2x | | 9z+11—5z=27 | | -3z+9=18 | | (7-2)^2+(6x-2)^3= | | -.06n=9.6 | | 1/2m+10=10 | | -2x-13=4x+6 | | 30+8x=2(1+6x) | | 5z+–15z=20 | | -(4.7k+4.4)/3=-3.3 | | -8(7-4x)=8(-7+5x) | | 2n+2+n+3n-1=18 | | 8b–2(2b+4)=8 | | x/4-6=14x= | | 4y-2=-50 | | 7(z+5)=77 | | 2.50x3x=13 | | 4x=6(5/3) | | 7(z+)=77 | | 5x+3=(6-x)=22 | | W=w+2 | | 11x+32x=172 |